If bx + cy = a,where a,b,c are of the same sign,be a line such that the area enclosed by the line and the axes of reference is 1/8 sq. unit then

A) b,a,c are in geometric progression.

B) b,2a,c are in geometric progression.

C) b,a/2,c are in arithmetic progression.

D) b,-2a,c are in geometric progression.

(More than one option is correct.)

### 1 Answer | Add Yours

Your equation of line is

`bx+cy=a`

Sustitute respectively y and x are 0 ,to get x and y interceps.

Thus

y=0 , `x=a/b`

and

x=0 `y=a/c`

Area of triangle formed by line and axes

=`(1/2)(a/b)(a/c)` (i)

But

`(1/2)a^2/(bc)=1/8` (given)

`4a^2=bc`

`(2a)^2=bc`

This implies b,2a,c are geometric progression

Appropriate answer be **B**

**D is ruled out because condition a,b,c are of the same sign.**

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