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A bus travels for x hours at a speed of (x+2) km/h. If the distance travelled is 15km,...
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Distance travelled `= (speed)xx(time)`
speed = (x+2)
Time = x
Distance travelled = 15
`x(x+2) = 15`
`x^2+2x = 15`
`x^2+2x-15 = 0`
`x^2+5x-3x-15 = 0`
`x(x+5)-3(x+5) = 0`
`(x-3)(x+5) = 0`
`x = 3` or `x = -5`
Since x represent time it cannot be a negative value. So x = 3.
Speed of the bus `= 3+2 = 5`
So the speed of the bus is 5km/h.
you better walk rather than going this kind of a bus. :)
Posted by jeew-m on July 17, 2013 at 10:35 AM (Answer #1)
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