# Bring the equation of the line 3x-4y-12=0 to the intercept form and find the intercept on the axis .

hala718 | High School Teacher | (Level 1) Educator Emeritus

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The standard for for the intercept is:

x/a + y/b = 1    where a is x-intercept and b is y-intercept;

We have the equation:

3x - 4y - 12 = 0

Move 12 to the right side:

==> 3x - 4y = 12

Now divide by 12:

==> 3x/12 - 4y/12 = 1

==> x/4 - y/3 = 1

==> x/4 + y/-3 = 1

Then x-intercept = 4

and y-intercept = -3

neela | High School Teacher | (Level 3) Valedictorian

Posted on

3x-4y-12 = 0. To bring to the intercept form.

Solution:

There are two types of intercept forms:

(i) slope and  intercept  form: y = mx+c , where m is slope and c is y intercept.

The given equation is 3x-4y -12 = 0. Add 4y.

3x-12 = 4y Divide by 4:

3x/4 -12/4 = y. Or

y = (3/4)x-3.

(ii) Double ntercept form: x/a +y/b =1, where a and b are the intercepts on x and y axis.

Given equation : 3x-4y  -12 = 0. Add 12.

3x-4y = 12. Divide by 12:

3x/12 -4y/12 = 1. Re write as:

x / (12/3)  + y/(12/-4) = 1. Or

x/4 + y/(-3) = 1.

Therefore 3x-4y -12 has the double intercept form x/4 +y/(-3) = 1.

So 4 is x intercept and -3 is y intercept.

x

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

The given form of the equation is the general form.

This general form of the equation of the line has to be reduced to the intercept form, that is:

x/a + y/b = 1

We'll write the given equation:

3x-4y-12=0

3x-4y = 12

We'll divide by 12 both sides, in order to obtain 1 to the right side:

3x/12 - 4y/12 = 12/12

x/4 - y/3 = 1

We'll re-write the equation:

x/4 + y/-3 = 1

So, the x intercept is 4 and the y intercept is -3.