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A box has chocolates which are divided among A, B and C in the ratio 4: 3: 1. If A gets...

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tonyah995 | Student, Undergraduate | Salutatorian

Posted February 25, 2011 at 1:10 PM via web

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A box has chocolates which are divided among A, B and C in the ratio 4: 3: 1. If A gets 32 chocolates more than C, how many does B get?

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted February 25, 2011 at 1:20 PM (Answer #1)

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Let the number of chocolates in the box be N. When they are distributed among A, B and C in the ratio 4: 3: 1, the number of chocolates that A gets is 4N/ 8 and C gets N/8 chocolates.

As A gets 32 more chocolates than C

4*N/8 - N/8 = 32

=> 3N/8 = 32

=> N = 32*8/3

B gets 3/8 of the total number of chocolates. This is equal to (32*8/3)*(3/8)

=> 32*8*3/8*3

=> 32

The number of chocolates that B gets is 32, though it should be noticed that the total number of chocolates in the box does not come to a whole number.

B gets 32 chocolates.

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