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The answer is $22 and $66 respectively. The way to get that answer is as follows:
Let the ball be X and they bag be Y.
x + y = 88
x = 3y
Now we substitute the value for x in the second equation into the first.
3y + y = 88
4y = 88
y = 22
So that tells us the price of the bag is $22.
If the price of the ball is 3 times that of the bag, 22*3 = 66.
We can also see this is true because 66 + 22 = 88.
Let us assume that the cost of the ball =x
The cost of the bag= y
Then the cost for both is:
But the cost of the ball = 3 times the cost of the bag
==> x= 3y
Now substitute with x=3y
==> x+y= 88
==> 3y+y= 88
==> 4y= 88
==> y= 88/4= 22
==> x= 3y= 3(22)= 66
Then the cost of the ball (x) = $66
and the cost for the bag (y)= $22
The condition that ball costs 3 times as much as the bag enables us to say ball costs 3x and the bag costs x. So the total cost is 3x+x = 4x which is actually $88. So the required equation is 4x = $88. Solving for x we get the cost of the bag. Therefore,
4x/4 = $88/4
x = $22, being the cost of bag.
Cost of the ball =3x = 3*$22 = $66.
There are two variable factors in this equation
let b= bowling ball price
let g= bag price
therefore, your system of equations is
you now can input 3g for b and your system of equations is now
now, simplify and solve your equation
now, substitute g in the previous equation b+g=88
The bowling ball costs 66 dollars and the bag costs 22 dollars
Hope this helps!
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let the cost of bag=x
Cost of ball=3*(Cost of bag)=3x
Cost of bag=x=$22
coat of ball=3*x=3*$22=$66
the cost of a bowling ball be x.
the cost of a bag be y.
then ACCORDING TO THE STATEMENT, we will get the following eqn
x + y =88[eqn 1]
now,the question says that ball costs 3 times as much as bag.
which implies that, x = 3y[eqn 2]
now by using the elimination method,
x + y =88
x = 3y which implies that x-3y=0
now multiplying eqn 1 by 3,we get
subtracting these two eqns, we get
which implies that, x=264/4
therefore cost of ball=x =66
cost of bag=y=22.
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