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A body A of 100 N weight is placed on a table. Another smaller body B of 50 N is placed...

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madmoni06 | Student | (Level 1) Honors

Posted May 2, 2013 at 3:13 PM via web

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A body A of 100 N weight is placed on a table. Another smaller body B of 50 N is placed on top of A.What is the force on (1) upper body B from the lower body A and (2) the lower body B from the table?

a. 150 N, 150 N

b. 100 N, 150 N

c. 50 N, 50 N

d. 50 N, 150 N

 

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted May 6, 2013 at 8:47 AM (Answer #1)

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Every action has an equal and opposite reaction. A body A of 100 N weight is placed on a table. Another smaller body B of 50 N is placed on top of A. The force exerted by the the smaller body B on the larger body A is equal to the weight of the body or 50 N. As both the bodies and stationary and do not accelerate, the net force acting on them is zero. On body A, the body B exerts a downward force of 50 N, the body A itself exerts a force of 100 N on the table. To make the net force zero, the tables exerts a force of 150 N on block A.

The force exerted on body B by body A is 50 N and the force exerted on body A by the table is 150 N.

The correct option is d.

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