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Biscuits are sold in packets of 18. There is a constant probability that any biscuit is...
Biscuits are sold in packets of 18. There is a constant probability that any biscuit is broken, independently of other biscuits. The mean number of broken biscuits in a packet has been found to be 2.7. Find the probability that a packet contains between 2 and 4 (inclusive) broken biscuits.
Please help me solve the question above.. I'm totally confused. An explanation will be appreciated!
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Posted by jspake on April 21, 2013 at 12:54 PM (Answer #2)
Let random selection of broken biscuit follows Binomial distribtion.
mean of binomial distribution= np
Probability of r broken biscuits.
probability that a packet contains between 2 and 4 (inclusive) broken biscuits = P(x=2)+P(x=3)+P(x=4)
Posted by pramodpandey on April 21, 2013 at 10:07 AM (Answer #1)
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