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# Between the points (5,4) and (-5,-4) find:  a) The distance (simplified radical) b)...

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Between the points (5,4) and (-5,-4) find:

a) The distance (simplified radical)

b) The midpoint (use .5 for 1/2)

Posted by kristenmariebieber on September 25, 2013 at 4:19 AM via web and tagged with algebra 2, math

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Between the points (5,4) and (-5,-4) find:

a) The distance (simplified radical)

b) The midpoint (use .5 for 1/2)

(a). The distance between given points `(x_1,y_1) and (x_2,y_2)` is

`sqrt((x_2-x_1)^2+(y_2-y_1)^2)`

Thus distance between (5,4) and (-5,-4) is

`=sqrt((5+5)^2+(4+4)^2)=sqrt(100+64)`

`=sqrt(164)=12.806`  unit ( aprox)

(b) Mid point of (5,4) and (-5,-4).

Let `(x_1,y_1)` be the mid point,

then

`x_1=(5-5)/2=0`

`y_1=(4-4)/2=0`

Thus mid will (0,0).

Posted by aruv on September 25, 2013 at 4:27 AM (Answer #1)

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