# Write the equation a = bc in logarithmic form.

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It is given that a = b*c.

Take the logarithm to any base B of both the sides.

`log_B a = log_B(b*c)`

Use the property `log_B a*b = log_B a + log_B b`

=> `log_B a = log_B b + log_B c`

**The given relation is equivalent to **`log_B a = log_B b + log_B c`

So that? Let ya explain more please: