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 A bag contains 4 red balls, 3 green balls, and 5 yellow balls. What is the...

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damdoomdima | Student, Grade 11 | eNoter

Posted June 22, 2010 at 7:16 AM via web

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 A bag contains 4 red balls, 3 green balls, and 5 yellow balls. What is the probability of drawing a red or a green ball?

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hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted June 22, 2010 at 7:20 AM (Answer #1)

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We have a bag contains:

4 red balls

3 green balls

5 yellow balls

Then the total number of balls in the bag is 12 balls

The chances of drawing a red ball = number of red balls / total number of balls = 4/12 = 1/3

The chances of drawing a green ball =  number of green balls/ total number of balls = 3/12 = 1/4

Now in probability the phrase OR translate as +

The the chances of drawing a red OR a green ball = chances of red + chances of green = 1/3 + 1/4 = 7/12

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brianevery | High School Teacher | (Level 2) Adjunct Educator

Posted June 22, 2010 at 7:21 AM (Answer #2)

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Probability is determined by the number of desired answers divided by the total number of answers. There are 12 possible balls you can draw so the denominator will be 12, there are 4 red balls and 3 green balls, so there are 7 balls that fit the requirement of being either red or green.

The probability of drawing either a red or a green ball is 7/12.

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