A bag contains 4 blue marbles, 5 red marbles, and 7 green marbles. If two marbles are drawn without any replacement, what is the probability that:

a) Both marbles are blue.

b) At least one marble is red.

c) The marbles are not of the same color.

### 2 Answers | Add Yours

The bag contains 4 blue marbles, 5 red marbles, and 7 green marbles. Two marbles are drawn without replacement.

The probability that both the marbles are blue is `(4/16)(3/15) = 0.05`

The probability that at least one marble is red is `2*(5/16)*(11/15) + (5/16)*(4/15) = 0.54`

The probability that the marbles are not of the same color is `(4/16)*(12/15) + (5/16)*(11/15) + (7/16)*(9/15) ~~ 0.691`

A= 0.05 (0.25x0.2)

B = 0.54 (2x0.3125x0.7333)+(0.3125x0.2666)

C= 0.69 (0.25x0.8)+(0.3125x0.7333)+(0.4375x0.6)

Hope that helps!!!

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes