A bag contains 4 blue marbles, 5 red marbles, and 7 green marbles. If two marbles are drawn without any replacement, what is the probability that:
a) Both marbles are blue.
b) At least one marble is red.
c) The marbles are not of the same color.
2 Answers | Add Yours
The bag contains 4 blue marbles, 5 red marbles, and 7 green marbles. Two marbles are drawn without replacement.
The probability that both the marbles are blue is `(4/16)(3/15) = 0.05`
The probability that at least one marble is red is `2*(5/16)*(11/15) + (5/16)*(4/15) = 0.54`
The probability that the marbles are not of the same color is `(4/16)*(12/15) + (5/16)*(11/15) + (7/16)*(9/15) ~~ 0.691`
A= 0.05 (0.25x0.2)
B = 0.54 (2x0.3125x0.7333)+(0.3125x0.2666)
C= 0.69 (0.25x0.8)+(0.3125x0.7333)+(0.4375x0.6)
Hope that helps!!!
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