If a and b are positive real numbers, show that

log_a b= 1/ log_b a

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Let us say;

`y = log_ab`

Now remove log from right side.

`a^y = b`

Now take log on both side with respect to base b.

`log_b(a^y) = log_bb`

`ylog_ba = 1`

`y = 1/(log_ba)`

We know that `y = log_ab`

`log_ab = 1/(log_ba)` *answer as required.*

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