1 Answer | Add Yours
Let us say;
`y = log_ab`
Now remove log from right side.
`a^y = b`
Now take log on both side with respect to base b.
`log_b(a^y) = log_bb`
`ylog_ba = 1`
`y = 1/(log_ba)`
We know that `y = log_ab`
`log_ab = 1/(log_ba)` answer as required.
We’ve answered 330,864 questions. We can answer yours, too.Ask a question