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Avg value of fun. over given interval..(please explain each step in detail bc I am...

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adb2188 | eNoter

Posted July 16, 2013 at 11:04 PM via iOS

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Avg value of fun. over given interval..(please explain each step in detail bc I am lost:( ) f(x)=2x+1 on [0,4].. THANK YOU!!!!

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted July 16, 2013 at 11:37 PM (Answer #1)

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A function f(x) that is closed in an interval (a,b) the its average value defined by `1/(b-a)int_a^bf(x)dx`

For our question;

`f(x) = 2x+1`

`a = 0`

`b = 4`

 

Average value

`= 1/(4-0)int_0^4(2x+1)dx`

`= 1/4[x^2+x]_0^4`

`= 1/4(16+4-0-0)`

`= 5`

 

So the average value of the function is 5.

 

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