Avg value of fun. over given interval..(please explain each step in detail bc I am lost:( ) f(x)=2x+1 on [0,4].. THANK YOU!!!!
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A function f(x) that is closed in an interval (a,b) the its average value defined by `1/(b-a)int_a^bf(x)dx`
For our question;
`f(x) = 2x+1`
`a = 0`
`b = 4`
So the average value of the function is 5.
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