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ans the following question please;  If a uniform spring is cut in half, what is the...

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ayaanali | Student, Undergraduate | (Level 1) eNoter

Posted November 21, 2010 at 3:12 PM via web

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ans the following question please;

 

If a uniform spring is cut in half, what is the force constant of each half? Justify your answer. How would the frequency of SHM using a half-spring differ from the frequency using the same mass and the entire energy?

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nessus | High School Teacher | (Level 2) Adjunct Educator

Posted July 10, 2011 at 8:45 PM (Answer #1)

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Hooke's Law is F = kx, where F = extension force, x = extension distance, k = spring constant (what you have called force constant)

Rearranging for k:

k = F/x.

The force required to stretch half a spring to the same length as the original is clearly twice (because the half spring is harder to stretch) so in the above equation k is doubled.

Frequency of SHM is twice that of the original spring because SHM frequency is proportional to k.

 

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