angus has a mass of 78kg. he is standing in a rocket leaving the surface of the moon and is standing on some bathroom scales. the scales read 514.8N. given that the acceeleration due to gravity of the moon is 1.62m/s2 determine the acceleration with which the rocket is leaving the moon.

### 1 Answer | Add Yours

Assume the acceleration of the rocket is a(`m/s^2` ).

Using the Newtons second law of motion;

When the rocket travels upward from moon the weight recorded on the scale depend on two factors.

1. Acceleration of rocket (`uarr a` )

2. Acceleration due to gravity of moon (`darr1.62` )

`uarrF = ma`

`514.8 = 78xx(a-1.62)`

`a = 514.8/78+1.62`

`a = 8.22`

*So the acceleration of the rocket is `8.22m/s^2` .*

**Sources:**

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes