Analysis of a compound known to contain only Mg, P,and O gives this analysis.21.8%  Mg, 27.7% P, 50.5% OWhat is its empirical formula?

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molecular weight

`Mg = 24`

`O = 16`

`P = 31`

 

Let us say we have 100g of compound.

Then we have 21.8g of Mg,27.7 of P and 50.5g of O.

Moles of Mg `= 21.8/24 = 0.908`

Moles of P `= 27.7/31 = 0.894`

Moles of O `= 50.5/16 = 3.156`

 

`M:P:O = 0.908:0.894:3.156 ~= 1:1:3.5 = 2:2:7`

 

So the empirical formulae would be `Mg_2P_2O_7`

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