# An umpire tosses up a coin with a speed of 10 m/s. If his hand is 1 m above the ground, how much total distance the coin will travel before hitting the ground ? a. 5 m b. 6 m c.10 m d.11 m

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Let us say the datum is at the level of umpires hand.

Using equations of motion under gravity for the travel of coin comes to max height.

`uarrv^2 = u^2+2gS`

`S = (v^2-u^2)/(2g)`

`S = (10^2-0)/(2xx9.81)`

`S = 5`

So it will come another 5m to the datum level and go further 1m down to reach the ground.

Total distance travelled by coin = 5+5+1 = 11m.

*So the answer is d.*

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