An umpire tosses up a coin with a speed of 10 m/s. If his hand is 1 m above the ground, how much total distance the coin will travel before hitting the ground ? a. 5 m b. 6 m c.10 m d.11 m  

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted on

Let us say the datum is at the level of umpires hand.

Using equations of motion under gravity for the travel of coin comes to max height.

`uarrv^2 = u^2+2gS`

`S = (v^2-u^2)/(2g)`

`S = (10^2-0)/(2xx9.81)`

`S = 5`

 

So it will come another 5m to the datum level and go further 1m down to reach the ground.

Total distance travelled by coin = 5+5+1 = 11m.

So the answer is d.

 

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