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If an object is thrown vertically upward with an initial velocity of v, from an...
If an object is thrown vertically upward with an initial velocity of v, from an originial position of s, the height at any given time t is given by:
h = -16t^2 + vt +s (h and s are in ft, t is in seconds, and v is in ft/sec)
A ball is thrown upward with an initial velocity of 96 ft/sec from the top of a 100 foot bridge. Determine the time that it takes for the ball to get to a height of 200 ft. Round answers to 2 decimals, separated by commas.
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High School Teacher
The height of the object at time t is given by:
We are given `s=100,v=96` and we are asked to find t when h=200. Substituting the values we get:
`4(4t^2-24t+25)=0` Use the quadratic formula on the expression in the parantheses:
The solutions are `t~~1.34"sec"` and `t~~4.66"sec"` ; the first as the ball rises, and then as it falls back down.
Posted by embizze on May 12, 2013 at 3:30 AM (Answer #1)
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