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An object initally moving at 6.8m/s E is accelerating at 2.0m/s2 W reaching a final...
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We can solve for the total distance using the following equation of motion:
Substitute what we know into the equation:
`v_1=6.8m/s` ; `v_2=10.2m/s` ; `a=2.0 m/s^2`
Therefore, the object has travelled 14.45m.
Posted by crmhaske on June 4, 2013 at 12:07 AM (Answer #1)
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