# An objectÂ is dropped from a height of 26.8 m. What is its average acceleration (assumed to be constant) if it hits the ground with a speed of 3.96 m/s?

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The object is *dropped* from a height of 26.8 m. As it is dropped, the initial velocity of the object is 0 m/s. It is assumed that the acceleration of the object is a constant over the entire distance that it falls. It hits the ground with a speed 3.96 m/s.

The relation between initial velocity (u), final velocity (v), displacement of an object (s) and its acceleration a is:

v^2 - u^2 = 2*a*s

Substituting the values in the problem:

3.96^2 - 0 = 2*26.8*a

=> a = 0.2925 m/s^2

The average acceleration of the object is 0.2925 m/s^2