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An incandesent light bulb has a resistance of 240 `Omega` when lighted. What is the...
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The relationship between the current, voltage and resistance is known as Ohm's Law:
`V = I*r` , where V is voltage, i is current and r is resistance.
Therefore the current through the 240 `Omega` bulb connected to 120-Volt source is
`I=V/r = (120 V)/(240 Omega) = 0.5` Amp
The current is 0.5 Amps.
Posted by ishpiro on June 2, 2013 at 7:25 PM (Answer #1)
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