An airplane is approaching an airport at an altitude of 300 feet.Looking directly downt eh runway, the pilot sights an angle of depression with a measure of 29 degrees to the near end of the runways, and one with a measure of 7 to the far end of the runway. Find the length of the runway?
http://www.ursulinestl.org/class_files/13/3072/25668.pdf this is the diagram .
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Please see the attached figure for a representation of the situation.
<LHF=<HFG= 7 degrees (opposite interior angles)
Similarly, <LHN=<HNG = 29 degrees (opposite interior angles)
Now consider `Delta HFG, tan 7^o=300/(GF)=300/(GN+FN)` --- (i)
Again from `Delta HNG, tan 29^o=300/(GN)` --- (ii)
From (i), `300/(tan29^o)+FN = 300/(tan7^o)`
Therefore, length of the runway was 1902 ft.
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