an 200g arrow in a 3.00 kg bow is pulled back with 80.0 N of force a distance of 70.0 cm and released.
a. determine the work done to the arrow (in J)
b. Dtermine the maximum speed of the arrow (in m/s)
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a. Holding in a hand of 3.kg bow ,here work is done against gavitationa force ,but actual work done is zero because displacement is perpedicular to drection of force.
Work done by arrow= Force x displacement
= 80 x (70/100) J
b. When arrow released , work will convert int energy. Let velocity of arrow be v m/s
work = energy (K.E.)
56 = (1/2) (200/1000)v^2
v^2=56 x 10
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