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An  18m long ladder is leaning against the wall of a building. the top of the ladder...

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yahhhh | Student, Grade 12 | Honors

Posted February 20, 2013 at 9:05 PM via web

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An  18m long ladder is leaning against the wall of a building. the top of the ladder reaches a window 11m above ground. if the ladder is tilted in the opposite direction, without moving its base, the top of the ladder can reach a window in another building that is 7 m above ground. How far apart, to the nearest metre, are the two buildings. 

 

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted February 21, 2013 at 1:46 AM (Answer #1)

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Let us say;

Distance from ladder base to building 1 = x

Distance from ladder base to building 1 = y

 

Then the distance between buildings will be x+y

 

According to Pythagorean law we can say;

`18^2 = x^2+11^2 -----(1)`

`18^2 = y^2+7^2 -----(2)`

 

From (1) we get `x = sqrt(18^2-11^2) = 14.25m`

From (2) we get `y = sqrt(18^2-7^2) = 16.58m`

 

So the distance between buildings`= x+y= 14.25+16.58 = 30.83m`

 

Distance between two buildings is 30.83m

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