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If `alpha` , `beta` are the roots of the equation `x^2-4x-3 =0` , then...
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`x^2-4x-3 = 0`
The roots of the above quadratic function is `alpha` and `beta` .
Then we know that;
`alpha+beta = -(-4)/1 = 4`
`alphaxxbeta = -3/1 = -3`
`(x+y)^2 = x^2+2xy+y^2`
`(x^2+y^2) = (x+y)^2-2xy`
So the answer is 19 and it is at E)
Posted by jeew-m on September 7, 2013 at 6:17 AM (Answer #1)
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