Al den is 12 feet longer than it is wide. If the den's area is 405 square feet, what are the dimensions of the room? (_,_)?
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Let, width of the room be x feet
Then its length = (x+12) feet
According to the given problem:
den's area = 405 square feet
`=(-12+-42)/2` =30/2=15 or -54/2=-27
Since dimensions cannot be negative, we get x=15
width=15 feet and length=(15+12) or 27 feet.
Therefore, the dimensions of the room are width=15 feet, length=27 feet
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