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According to the equationSnO2 + 2H2 -> Sn + 2H2OWhat volume of H2, measured at 1 atm...
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`SnO_2 + 2H_2 rarr Sn + 2H_2O`
Molar mass of `SnO_2 = 150.7gmol`
Amount of `SnO_2` moles in 2g of `SnO_2 = 2/150.7=0.0133`
`SnO_2:H_2 = 1:2`
Amount of` H_2` required `=0.0133xx2=0.0266`
Using `PV = nRT`
So the volume of `H_2` required is 0.596L
Posted by jeew-m on August 24, 2013 at 3:15 AM (Answer #1)
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