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Find the height of the pass.Owen drops a stone from the top of a mountain pass. If it...
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We are given that Owen drops a stone from the top of a mountain pass. It takes 12 seconds to reach the valley bellow, the value of acceleration due to gravity is 9.8m/s^2 and we have to find the height of the pass. Let the height of the pass be d.
Now the speed of the stone when it strikes the bottom is u + at = 0+9.8*12 = 117.6 m/s
The distance travelled is given by 1/2 ( Vf + Vi ) × t .
Here Vi = 0, Vf = 117.6 , t = 12
Therefore the height d= 117.6*(1/2)*12 = 705.6
The height of the pass is 705.6 m.
Posted by justaguide on November 28, 2010 at 12:22 AM (Answer #1)
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