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ABC is an equilateral tiangle.P is any point on the arc BC.Prove AP=BP+PC...
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High School Teacher
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Since the points ABPC lie on a common circle, then the quadrilateral is cyclic (see link below). Cyclic quadrilaterals obey Ptolemy's theorem, so we have :
`AP cdot BC= AC cdot BP+PC cdot AB`
but since triangle ABC is equilateral, each side is the same. Let
then Ptolemy's Theorem becomes
`AP cdot x=x cdot BP+PC cdot x` divide both sides by x to get
The theorem has been proven.
Posted by lfryerda on September 18, 2012 at 1:57 AM (Answer #1)
Salutatorian, Dean's List
Posted by topperoo on September 11, 2012 at 4:25 AM (Answer #2)
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