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8 chairs are placed at the sides of a long table in such a way that three are 4 chairs...
8 chairs are placed at the sides of a long table in such a way that three are 4 chairs on the left and 4 chairs on the right. 8 children are to be seated on these chairs. If 2 specific children want to sit on the same side, calculate the number of ways all the 8 children can be seated.
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Let the two sides of the long table be A and B.
Two children who wish to sit on the same side (say, side A) can be accommodated in two chairs in either of the sides in `2*^4P_2` ways. Now six children are left who can sit on six chairs on both the sides of the table in 6! ways.
Hence, the total number of ways in which 8 children can be seated
= `2*^4P_2 * 6!`
Posted by llltkl on June 10, 2013 at 2:04 PM (Answer #1)
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