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If the 60 kg player is running forward at 7.0 m/s when she makes contact with the...
If the 60 kg player is running forward at 7.0 m/s when she makes contact with the dummy, what is the player’s velocity at the end of the 1.20 s impact?
Please can somebody tell me I am doing it right!!
Impulse can be calculated using either equation:
Fnet (difference Time)=(difference P(momentum)) or
Fnet ( difference Time)=m x (difference velocity)
If mass m is constant, then the only quantity changing on the right-hand side of the equation is V(velocity). So the equation becomes:
Fnet (difference Time)=m x (difference Velocity)
Given I= -360Ns , m=60kg, V initial=7.0 m/s
I impulse = m x (vf - vi)
Vf = 1.0 m/s
1 Answer | add yours
Posted by ishpiro on May 3, 2013 at 2:03 AM (Answer #1)
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