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A 542.5 sample g of manganese oxide has MnO ratio of 1.0 : 1.42 and consists of...
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Here ratio of Mn3O4:MnO=1.42:1.0
Therefore 1.42g of Mn3O4 consists 1.0g of MnO.
So in the sample mass of MnO = (1/1.42)*542.5g =382.04g
We have Mn2O3 and MnO in the Mn3O4 sample.
If weight of MnO is 382.04g,
Then weight of Mn2O3 = 542.5-382.04 = 160.46g
mass of Manganosite = 382.04g
mass of Braunite = 160.46g
Braunite (Mn2O3) have Mn^+3. One Mn2O3 gives two Mn^+3.
Manganosite (MnO) have Mn^+2. One MnO gives one Mn^+2.
So we need two Mn^+3 and one Mn^+2 to form one Mn3O4.
Mn^+3:Mn^+2 = 2:1
Posted by jeew-m on July 24, 2012 at 1:36 PM (Answer #1)
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