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A 500-kg elevator is pulled upward with a constant force of 5500N for a distance of...

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melehat | eNotes Newbie

Posted October 26, 2013 at 5:39 PM via web

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A 500-kg elevator is pulled upward with a constant force of 5500N for a distance of 50.0 m. What is the net work done on the elevator?

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kavya--kammana | Student, Grade 12 | Valedictorian

Posted October 28, 2013 at 7:02 AM (Answer #2)

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work done to lift the body= massx9.8xdistance ( F.S)

                                    500 x 9.8 x 50

                                  = 245000 J

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted October 26, 2013 at 5:48 PM (Answer #1)

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A 500 kg elevator is pulled upward with a constant force of 5500 N for a distance of 50.0 m

The net work done on the elevator as it moves upwards is stored in the form of gravitational potential energy. The difference in the potential energy of the 500 kg elevator at the point it is initially and at the point 50 m upwards is m*g*h = 500*9.8*50 = 245000

The net work done on the elevator as it is moved upwards 50 m due to the force acting on it is equal to 245 kJ.

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