# 5-2(4-2x)=21Can you help me find x ???

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5-2(4-2x)=21 First we distribute

5-(2(4)-2(2x))=21 Continue distributing

5-(8-4x) = 21 Change the sign of everything we are subtracting

5 - 8 + 4x = 21 Simplify

-3 + 4x = 21 Add 3 to both sides

-3 + 3 + 4x = 21 + 3 simplify

4x = 24 Divide by 4

x = 6 Our answer. Check 5-2(4-2(6))=5-2(4-12)=5-2(-8)=5-(-16)=5+16=21

5-2(4-2x)=21

distribute -2

5 - 8 + 4x =21

combine like terms

-3 + 4x = 21

add 3

4x = 21 + 3

combine like terms

4x = 24

now divide by 4

x = 6

5-2(4-2x)=21

distribute the 2

5 - 8 + 4x =21

combine like terms:

-3 + 4x = 21

add 3 to both sides:

4x = 21 + 3

combine like terms again:

4x = 24

now divide by 4x

x = 6

5 - 2 ( 4 - 2x ) = 21

To solve this equation , first distribute the 2

By distributing the 2 , you should get

5 - 8 + 4x = 21 now combine the like terms ( which is 5 and -8 )

By combining the like terms , you should get

-3 + 4x = 21 now add 3 on both sides

By adding 3 on both sides , you should get

4x = 24 now divide both sides by 4 .

By dividing both sides by 4 , you should get

x = 6 which is your answer

5-2(4-2x)=21

5-8+4x=21

-3+4x=24

4x/4=24/4

y=6

@hockeypuck124

Ummm... I think something went wrong in your equation. @beckden did it right because in your first step you combined the terms from

5-2(4-x)=21

to

3(4-2x)=21

You're not supposed to subtract two terms that are not of the same type i.e you're should do the multiplying part first:)

Hope this helps:$

I didnt get the same answer as above, but I'm doing this now in my math class and this is what I did.

5-2(4-2x)=21

First combine like terms. 3(4-2x)=21.

Next divide by 3 on both sides. (4-2x)=7

Then to get rid of the parenthesis you use square root. 4-2x= + or - the square root of 7.

Then subtract by 4 on both sides. -2x=-4 + or - the square root of 7.

Last divide by -2 on both sides. x=2 + or - the square root of 7.