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3 loads with same sign, are linked between them with 2 wires which have the length...
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Because we don't have forces in horizontal plane, and gravitational forces are balanced by normal reactions, the system is in equilibrium. We'll write the equilibrium condition for the load q1 and q2
T1=F12+F13=[q1*q2/(4*pi*eps*l^2)]+[q1*q3/(4*pi*eps*4*l^2)]=[q1(q2 + (q3/4))]/(4*pi*eps*l^2)]=14.4N
T2=F32+F31==[q3*q2/(4*pi*eps*l^2)]+[q1*q3/(4*pi*eps*4*l^2)]=[q3(q2 + (q1/4))]/(4*pi*eps*l^2)]=21.6N
For verifying, we'll write the equilibrium condition for q2:
T1+F23=T2+F21 (action and reaction)
Posted by giorgiana1976 on June 29, 2009 at 4:48 AM (Answer #1)
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