3 batteries develop the same power P=9W on a resistor, no matter if the link is serial or parallel. What power will develop a single battery?

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Posted on

P=R[nE/(R+r*n)]^2=R[E/(R+r/n)]^2, so R=r

P=R[nE/(R+R*n)]^2=(E^2/R)[n/(n+1)^2]

P1=R[E/(R+R)]^2=E^2/(4R)=(P/4)[(n+1)/n]^2

P1=4.0W

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