∫〖(〖2x〗^3+x^2)/x^2 dx=Ax^2-Bx+c〗;(A+B)^2=

### 1 Answer | Add Yours

`int(2x^3+x^2)/x^2dx`

`= int((2x^3)/x^2+x^2/x^2)dx`

`= int(x+1)dx`

`= x^2/2+x+c` where c is a constant.

If we comapre the solution with `Ax^2-Bx+c` ;

`Ax^2-Bx+c = x^2/2+x+c`

`A = 1/2`

`B = -1`

Then;

`(A+B)^2 = (1/2-1)^2 = 1/4`

*So the answers are;*

`A = 1/2`

`B = -1`

`(A+B)^2 = 1/4`

**Sources:**

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes