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If (2x + 1/3x) = 5, then find the value of 5x/(6x^2 + 20x + 1).a.1/7b.16/7c.16/27d.6/27

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nasirjam | Student, Grade 9 | Honors

Posted March 4, 2013 at 11:25 AM via web

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If (2x + 1/3x) = 5, then find the value of 5x/(6x^2 + 20x + 1).

a.1/7

b.16/7

c.16/27

d.6/27









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1 Answer | Add Yours

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted March 4, 2013 at 11:32 AM (Answer #1)

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`(2x + 1/3x) = 5`

 

`(2xxx3x+1)/3x = 5`

`(6x^2+1) = 15x`

 

`(5x)/(6x^2 + 20x + 1)`

`= (5x)/(6x^2 + 1+20x)`

`= (5x)/(15x+20x)`

`= (5x)/(35x)`

`= 5/35`

`= 1/7`

 

So the answer is` (5x)/(6x^2 + 20x + 1) =1/7`

 

Correct answer is a).

 

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