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If (2x + 1/3x) = 5, then find the value of 5x/(6x^2 + 20x + 1).a.1/7b.16/7c.16/27d.6/27
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`(2x + 1/3x) = 5`
`(2xxx3x+1)/3x = 5`
`(6x^2+1) = 15x`
`(5x)/(6x^2 + 20x + 1)`
`= (5x)/(6x^2 + 1+20x)`
So the answer is` (5x)/(6x^2 + 20x + 1) =1/7`
Correct answer is a).
Posted by jeew-m on March 4, 2013 at 11:32 AM (Answer #1)
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