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2N2O5(g) ->4NO2(g) + O2(g) The rate of disappearance of N2O5(g) at a certain...
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`2N_2O_5(g) -gt4NO_2(g) + O_2(g) `
From the stoichiometry of the reaction:
where `(dx)/dt` stands for rate of appearance or disappearance of species `x` with respect to time.
Here, the rate of disappearance of `N_2O_5` (g) at a certain temperature is 0.016 mol.L-1min-1.
Therefore, the the rate of formation of `NO_2` (g) at this temperature
= 2*0.016 =0.032 mol.L-1min-1.
Posted by llltkl on August 20, 2013 at 4:48 AM (Answer #1)
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