25x^2 + 5 = 14

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The equation 25x^2 + 5 = 14 has to be solved for x.

25x^2 + 5 = 14

=> 25x^2 = 14 - 5

=> 25x^2 = 9

=> x^2 = 9/25

x = `+-3/5`

**The solution of the equation is `+-3/5` **

Given equation is `25x^2+5=14`

or, `25x^2+5-14=0`

or, `25x^2-9=0`

or, `((5x)^2-3^2)=0`

As `a^2-b^2=(a-b)(a+b)`

so, `(5x-3)(5x+3)=0`

Now, `(5x-3)=0rArr5x=3`

or, `x=3/5` ,

`(5x+3)=0rArr5x=-3`

or, `x=-3/5` .

So `x=+-3/5` .

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