A 256 turn coil with a cross sectional area of 0.0025m^2 is placed in a uniform external magnetic field of strength 0.25 T so that the plane of the coil is perpendicular to that of the field. The coil is pulled steadily out of the field in 0.75s. Can you find the average induced emf during this interval?

### 1 Answer | Add Yours

The magnitude of the induced emf is

`epsi=(Nphi)/(Deltat)` V

where `phi=` magnetic flux ,

`phi=BA cos(0^o)`

`=.25xx.0025=6.25xx10^(-4)` `Tm^2`

N= number of turns=256 ,

`Deltat` =.75s

`epsi=(256xx6.25xx10^(-4))/(.75)=2.133xx10^(-1)V`

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes