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A 256 turn coil with a cross sectional area of 0.0025m^2 is placed in a uniform...

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lkehoe | Valedictorian

Posted April 11, 2013 at 9:33 PM via web

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A 256 turn coil with a cross sectional area of 0.0025m^2 is placed in a uniform external magnetic field of strength 0.25 T so that the plane of the coil is perpendicular to that of the field.  The coil is pulled steadily out of the field in 0.75s.  Can you find the average induced emf during this interval?

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pramodpandey | College Teacher | Valedictorian

Posted April 12, 2013 at 5:35 AM (Answer #1)

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The magnitude of the induced emf is

`epsi=(Nphi)/(Deltat)` V

where `phi=` magnetic flux ,

`phi=BA cos(0^o)`

`=.25xx.0025=6.25xx10^(-4)` `Tm^2`

N= number of turns=256 ,

`Deltat` =.75s

`epsi=(256xx6.25xx10^(-4))/(.75)=2.133xx10^(-1)V`

 

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