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A 250.0 kg mass is fired horizontally off a 40.0 cliff with a velocity of 30.0m/s. a....
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The velocity of the object when it is fired horizontally off the cliff is 30 m/s. The mass of the object is 250 kg and the height of the cliff is 40 m.
As the mass leaves the edge of the cliff there is a downward acceleration of 9.8 m/s^2 due to the gravitational pull of the Earth. If the time taken by the object to hit the ground is t, use the formula s = u*t + (1/2)*a*t^2, here u = 0, a = 9.8
40 = (1/2)*9.8*t^2
=> t = `sqrt(80/9.8)`
=> `t ~~ 20/7` s
The horizontal distance from the cliff where the object lands is given by `30*(20/7)` = `600/7` m
Posted by justaguide on July 12, 2013 at 3:34 AM (Answer #1)
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