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A 200 g mass attached to a horizontal spring oscillates at a frequency of 2.0 Hz. At t...
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- k = spring constant (?)
- m = mass of the object = 200 g or 0.200 kg
- F = frequency = 2.0 Hz
We know that the angular frequency can be expressed in different forms.
`omega = (2*pi)/(T)`
`omega = 2*pi*F`
`omega = sqrt(k/m)`
By equating 1 and 3 we can solve for the spring constant.
`k =(2*pi*F)^2 * m`
`k = (2*pi*2.0)^2 * 0.2`
k = 31.6 -> answer
Posted by jerichorayel on April 11, 2013 at 3:39 PM (Answer #1)
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