2+1/{x+1/(y+1/z)}=37/13 Find the values of x,y and z.(numerical values)Please solve this question...

1 Answer | Add Yours

sciencesolve's profile pic

Posted on

Since the problem provides only one equation and three unknowns, x,y,z, then you cannot find the numerical values of each unknown, because the number of variables overcome the number of given equation.

You can find the numerical values of x,y,z only if the problem provides two more relations that involve x,y and z.

The only thing you can do is to find an equation that relates the variables x,y and z such that:

`2 + 1/(x + 1/(y + 1/z)) = 37/13`

`2 + 1/(x + z/(yz + 1)) = 37/13`

`2 + (yz + 1)/(xyz + x + z) = 37/13`

`(2xyz + 2x + 2z + yz + 1)/(xyz + x + z) = 37/13`

`37xyz + 37x + 37z = 26xyz + 26x + 26z + 13yz + 13`

`11xyz + 11x + 11z = 13yz + 13`

`11(xyz + x + z) = 13(yz + 1)`

Hence, evaluating the equation that relates the variables x,y and z yields `11(xyz + x + z) = 13(yz + 1).`

We’ve answered 330,827 questions. We can answer yours, too.

Ask a question