# (17c^6+12c^5-3c^3+2c^2+9)+(5c^6-8c^4+9c^3+11c^2-5c-6)simplify and solve each polynomial.write it in standard form.

### 4 Answers | Add Yours

Since the two parenthetical expressions are added, we can simply ignore the parentheses. (If they were subtracted, all the +s and -s in the second one would have to be switched.)

Now just find the ones that have the same exponent, since you can't combine ones that are raised to different powers.

17c^6 + 5c^6 = 22c^6

12c^5 stands alone - there is no other c^5

-8c^4 stands alone - there is no other c^4

-3c^3 + 9c^3 = 6c^3

2c^2 + 11c^2 = 13c^2

-5c stands alone - there is no other c

9 - 6 = 3

So, we are left with:

22c^6 + 12c^5 - 8c^4 + 6c^3 + 13c^2 - 5c + 3

### (17c^6+12c^5-3c^3+2c^2+9)+(5c^6-8c^4+9c^3+11c^2-5c-6)

= (17+5)c^6+12c^5-8c^4 (-3+9)c^3+(2+11)c^2-5c+9-6

= **22c^6+12c^5-8c^4+6c^3+13c^2-5c+3**

In order to solve this problem, add numbers with same variables.

(17c^6+12c^5-3c^3+2c^2+9)+(5c^6-8c^4+9c^3+11c^2-5c-6)

22c^6+1c^5-8c^4++6c^3+13c^2-5c+3

After opening the parentheses, we try to group terms which have the same exponents, like this:

*c^6(17+5) + 12c^5 - 8c^4+ c^3(-3+9) + c^2 (2+11) - 5c + (9-6)=*

**22c^6 + 12c^5 - 8c^4 + 6c^3 + 3c^2 - 5c + 3 **