(17c^6+12c^5-3c^3+2c^2+9)+(5c^6-8c^4+9c^3+11c^2-5c-6)simplify and solve each polynomial.write it in standard form.

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cburr's profile pic

Posted on

Since the two parenthetical expressions are added, we can simply ignore the parentheses.  (If they were subtracted, all the +s and -s in the second one would have to be switched.)

Now just find the ones that have the same exponent, since you can't combine ones that are raised to different powers.

17c^6 + 5c^6 = 22c^6

12c^5 stands alone - there is no other c^5

-8c^4 stands alone - there is no other c^4

-3c^3 + 9c^3 = 6c^3

2c^2 + 11c^2 = 13c^2

-5c stands alone - there is no other c

9 - 6 = 3

So, we are left with:

22c^6 + 12c^5 - 8c^4 + 6c^3 + 13c^2 - 5c + 3

revolution's profile pic

Posted on


= (17+5)c^6+12c^5-8c^4 (-3+9)c^3+(2+11)c^2-5c+9-6

= 22c^6+12c^5-8c^4+6c^3+13c^2-5c+3

dracomath's profile pic

Posted on

In order to solve this problem, add numbers with same variables.



giorgiana1976's profile pic

Posted on

After opening the parentheses, we try to group terms which have the same exponents, like this:

c^6(17+5) + 12c^5 - 8c^4+ c^3(-3+9) + c^2 (2+11) - 5c + (9-6)=

22c^6 + 12c^5 - 8c^4 + 6c^3 + 3c^2 - 5c + 3 

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