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(17c^6+12c^5-3c^3+2c^2+9)+(5c^6-8c^4+9c^3+11c^2-5c-6)simplify and solve each...
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Middle School Teacher
Since the two parenthetical expressions are added, we can simply ignore the parentheses. (If they were subtracted, all the +s and -s in the second one would have to be switched.)
Now just find the ones that have the same exponent, since you can't combine ones that are raised to different powers.
17c^6 + 5c^6 = 22c^6
12c^5 stands alone - there is no other c^5
-8c^4 stands alone - there is no other c^4
-3c^3 + 9c^3 = 6c^3
2c^2 + 11c^2 = 13c^2
-5c stands alone - there is no other c
9 - 6 = 3
So, we are left with:
22c^6 + 12c^5 - 8c^4 + 6c^3 + 13c^2 - 5c + 3
Posted by cburr on December 7, 2008 at 11:42 AM (Answer #1)
After opening the parentheses, we try to group terms which have the same exponents, like this:
c^6(17+5) + 12c^5 - 8c^4+ c^3(-3+9) + c^2 (2+11) - 5c + (9-6)=
22c^6 + 12c^5 - 8c^4 + 6c^3 + 3c^2 - 5c + 3
Posted by giorgiana1976 on December 7, 2008 at 8:06 PM (Answer #2)
In order to solve this problem, add numbers with same variables.
Posted by dracomath on December 28, 2008 at 12:40 AM (Answer #3)
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