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A 15.00 mL sample of NaOH was titrated to the stoichiometric point with 17.40 mL of...
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First, we need to write the chemical equation for this reaction:
`NaOH + HCl -> NaCl + H_2O`
Looking at the balanced chemical equation we can see that there is 1:1 ration between the two reactants. Therefore:
`Mol es HCl = Mol es NaOH`
To determine the molar concentration of the NaOH solution, first we need to get the moles of HCl.
`Mol es HCl = (17.40)/(1000) L * 0.2340 M = 0.0040716 mol es HCl`
Since we know that moles of HCl are equal to the moles of NaOH, therefore:
moles HCl = moles NaOH = 0.0040716
`Molarity of NaOH = (mol es NaOH)/(volume of solution (L))`
`Molarity of NaOH = (0.0040716)/(0.015)`
Molarity of NaOH = 0.2714 M
Posted by jerichorayel on April 23, 2013 at 3:17 PM (Answer #1)
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