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A 15.00 mL sample of HCl solution of unknown concentration was titrated with .185 M...
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`Ca(OH)_2+2HCl rarr CaCl_2+2H_2O`
`Ca(OH)_2:HCl = 1:2`
Amount of `Ca(OH)_2` consumed `= 0.185/1000xx23.9 = 0.00442`
Amount of HCl moles reacted `= 2xx0.00442`
Let us say the concentration of the HCl solution is M.
`M/1000xx15 = 2xx0.00442`
`M = 0.5893`
So the concentration of the unknown HCl solution is 0.5893M.
Posted by jeew-m on September 2, 2013 at 6:05 AM (Answer #1)
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