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# `104= (1/2)*[(360-x)-x]`

schooledmom | Salutatorian

Posted June 20, 2013 at 1:49 PM via web

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`104= (1/2)*[(360-x)-x]`

Tagged with algebra 1, math

mvcdc | Student , Undergraduate | (Level 1) Associate Educator

Posted June 20, 2013 at 2:16 PM (Answer #1)

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We want to solve for x in:` `

`104 = (1/2)*[(360-x)-x]`

First, let us get rid of all the brackets and parentheses.

We can easily get rid of the inner parenthesis since it is only telling us to subtract x from 360 first before subtracting x again, which is only equivalent to:

`360-x-x = 360 - 2x`

Hence,

`104 = (1/2)*[360-2x]`

Now, we distribute `1/2`  to get rid of the brackets.

`104 = (1/2)*360 - (1/2)*2x`

`104 = 180 - x`

`104 - 180 = -x`

`x = 180 - 104`

`x = 76`

Hence, x = 76.

[Check:

`104 = (1/2)*[(360 - 76) - 76]`

`104 =(1/2)*[(284)-76]`

`104 = (1/2)*208`

`104=104`

]

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