# Within a \$100 budget for swimming classes what is the maximum number classes that can be attended if it costs \$50 to join the swimming association and \$5 for each class.

justaguide | College Teacher | (Level 2) Distinguished Educator

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The budget of the person who wants to join swimming classes is \$100. First, the person has to join the swimming association which costs \$50. This leaves \$100 - \$50 = \$50 with the person. As each swimming class costs \$5 the maximum number of classes the person can attend is 50/5 = 10.

In the given budget the person can attend a maximum of 10 swimming classes.

mikbjorn | Student, Undergraduate | (Level 1) eNoter

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Ok, so every inequality has two sides, the first thing to decide is what you want on each side. This problem gives you a budget, and costs. So for starters we have:

Budgets >= total costs

Now we need to decide what those two things are equivalent to. First, budget is how much money we have, \$100. So, our inequilty becomes:

\$100 >= total costs

Next, we need to determine what the costs consist of. There is a \$50 flat fee for joining. In addition, each class is going to cost \$5 additional. Since we do not know how many classes we are taking, we will let the number of classes be x. If we multiply the number of classes, x, by the cost per class then add the \$50 flat fee, our inequality becomes:

\$100 >= (\$5 * x) + \$50

Now that we have our inequality we must solve for x to see how many classes we can take within our budget. First we subtract \$50 from both sides, resulting in:

\$50 >= \$5 * x

Next we divide both sides by \$5 to get x by itself, resulting in:

10 >= x

So, we can take at most 10 classes and remain in budget.