Homework Help

Using the information for #1...

user profile pic

swimmers | Student | Honors

Posted March 25, 2012 at 2:39 PM via web

dislike 1 like

Using the information for #1 at http://gaberosenbaum.com/Champlain/NYA/2011_Winter/Excercises/NYA_PS_Work_Energy.pdf determine the work and motion of the 10.0 kg object.

1 Answer | Add Yours

user profile pic

mwmovr40 | College Teacher | (Level 1) Associate Educator

Posted March 29, 2012 at 9:15 AM (Answer #1)

dislike 1 like

For simple mechanical systems, work can be defined as the force applied times the distance an object travels in the direction of the force.  or W = Fdcos(theta)

If we assume from the information on the assigned web site that the object and force are co-directional, we can determine the amount of work by calculating the area under the line.

W = 40NX1m + 10NX4m + 0NX4m = 80 joules.

So, the total work is 40 joules.

According to the work energy theorem, the change in total mechanical energy of the object will be equal to the work applied.  If we again assume that the object is not changing height due to the work, then the entire amount of work will go into changing the object's kinetic energy.

W = KEf - KEi.  Because the initial speed is 0, the initial kinetic energy = 0, thus the work will be equal to the final kinetic energy

KE = W

1/2 MV^2 = W

V^2 = 2W/M

V = sqrt(2W/M) = sqrt(80/10) = sqrt(8) = 2.83 m/s

Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes